Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
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Exercise 14 Page 543

Substitute - 6 for x into the function rule.

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Using the function h(x)=x^2+6x, we want to evaluate for the given value, h( -6). To do this, we need to substitute - 6 for x in each instance of the x-variable.

x^2+6x
( - 6)^2+6( - 6)
36+6(-6)
36+(-36)
36-36
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