Substitute values for n=3,7, and 10 to find the terms.
18,34,46
Practice makes perfect
We are given an explicit rule of a sequence and are asked to find the third, seventh, and tenth terms.
A(n)=10+(n-1)(4)
To do so, we will construct a table.
n
A(n)=10+(n-1)(4)
A(n)
3
A( 3)=10+( 3-1)(4)
18
7
A( 7)=10+( 7-1)(4)
34
10
A( 10)=10+( 10-1)(4)
46
The third, seventh and tenth terms of this explicit sequence are 18, 34, and 46.
