Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
7. Scatter Plots and Trend Lines
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Exercise 19 Page 342

Begin by making a scatter plot of the data. A trend line is a line drawn on the scatter plot that is as close to as many data points as possible.

About 7 centimeters

Practice makes perfect

We have been given the following table that shows the relationship between the diameters and circumferences of the tops of a variety of cylinders.

Cylinders Tops
Diameter (cm) 3 3 5 6 8 8 9.5 10 10 12
Circumference (cm) 9.3 9.5 16 18.8 25 25.6 29.5 31.5 30.9 39.5

We will make a scatter plot of the data. Let's start with plotting the data. Let the x-axis represent the diameter and the y-axis represent the circumference.

Now, we can draw a trend line.

Next, we will write an equation for the trend line in slope-intercept form. y= mx+ b In this form, m is the slope and b is the y-intercept. First, let's find the slope by using the Slope Formula. m=y_2-y_1/x_2-x_1 In the formula, (x_1,y_1) and (x_2,y_2) represent the points that are on the line. There are many points that appear to be on the line. Let's choose the points (3,9.3) and (6,18.8) and substitute them into the formula.

m=y_2-y_1/x_2-x_1
m=18.8- 9.3/6- 3
m=9.5/3
m=3.16666
m≈ 3.2

The slope of the trend line is approximately 3.2. y=3.2x+ b Next, we will find the y-intercept by substituting the point (3,9.3) into this equation.

y=3.2x+b
9.3=3.2( 3)+b
9.3=9.6+b
-0.3=b
b=-0.3

From here, we can write the complete equation. y=3.2x-0.3 Finally, we can estimate the diameter of a cylinder with a circumference of 22 centimeters. Since the y-axis represents the circumference, we will substitute 22 for y into the equation and solve it for x, which is the diameter.

y=3.2x-0.3
22=3.2x-0.3
22.3=3.2x
6.96875=x
7≈ x
x≈ 7

As a result, the diameter is approximately 7cm.