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Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
6. Formalizing Relations and Functions
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Exercise 41 Page 273

To calculate the function's value when x=0.75, substitute 0.75 for x.

5.25

Practice makes perfect

To calculate the function's value, we substitute 0.75 for x into the function rule.

f(x)=7x
Substitute

x= 0.75

f( 0.75)=7( 0.75)
Multiply

Multiply

f(0.75)=5.25
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arrow_right Lesson Check p.271
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Lesson Check 2 (Page 271)
Lesson Check 3 (Page 271)
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Lesson Check 6 (Page 271)
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arrow_right Practice and Problem-Solving Exercises p.271-273
Practice and Problem-Solving Exercises 8 (Page 271)
Practice and Problem-Solving Exercises 9 (Page 271)
Practice and Problem-Solving Exercises 10 (Page 271)
Practice and Problem-Solving Exercises 11 (Page 271)
Practice and Problem-Solving Exercises 12 (Page 271)
Practice and Problem-Solving Exercises 13 (Page 271)
Practice and Problem-Solving Exercises 14 (Page 271)
Practice and Problem-Solving Exercises 15 (Page 271)
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Practice and Problem-Solving Exercises 22 (Page 272)
Practice and Problem-Solving Exercises 23 (Page 272)
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Practice and Problem-Solving Exercises 28 (Page 272)
Practice and Problem-Solving Exercises 29 (Page 272)
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Practice and Problem-Solving Exercises 37 (Page 273)
Practice and Problem-Solving Exercises 38 (Page 273)
Practice and Problem-Solving Exercises 39 (Page 273)
Practice and Problem-Solving Exercises 40 (Page 273)
arrow_right Standardized Test Prep p.273
Standardized Test Prep 41 (Page 273)
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arrow_right Mixed Review p.273
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