Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
6. Formalizing Relations and Functions
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Exercise 40 Page 273

Find g(3). Then, substitute it for x in f.

20

Practice makes perfect

We are given two functions. f(x)&=2x g(x)&=x^2+1 We need to evaluate them for certain values of x. In this case, we need to find f( g(3) ). This means we need to find the value of the function g(x) when x=3 and substitute the answer for x in f.

Value of g(3)

Let's start by finding the value of g(3). To do this, substitute 3 for x in the function rule.

g(x)=x^2+1
g( 3)=( 3)^2+1
g(3)=9+1
g(3)=10

When x=3, g(x)= 10.

Value of f(g(3))

Now, we have to find the value of f( g(3) ). To do this, substitute g(3), which is 10, for x in the function rule.

f(x)=2x
f( 10)=2( 10)
f(10)=20

Therefore, f( g(3) )= 20.