Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
6. Formalizing Relations and Functions
Continue to next subchapter

Exercise 23 Page 272

Given the limitations of the jug, what are the possible c-values?

Domain: 0 ≤ c ≤ 16
Range: 0 ≤ V(c) ≤ 1568
Graph:

Practice makes perfect

We will first determine domain and range of the function shown below. V(c) = 98c Then, we will draw its graph.

Determining the Domain

Because c represents the number of cups of milk the jug can hold, the smallest possible value is c= 0. Notice that c cannot take any negative values, as it does not make sense for a jug to hold negative cups of milk. 0 ≤ c It is given that the jug can hold 16 cups. That means the maximum value is c= 16, as the jug physically cannot hold more milk. c ≤ 16 Then, a reasonable domain for this situation is the combination of the above intervals. Domain: & 0 ≤ c ≤ 16

Determining the Range

We can now use the domain to determine the corresponding range. Since the function is a straight line, the minimum and maximum values of the domain will determine the minimum and maximum range. Let's substitute c=0 and c=16 into the given function rule.

c 98c V(c)=98c
0 98( 0) 0
16 98 ( 16) 1568

As the minimum and maximum values of V are 0 and 1568, respectively, a reasonable range for this situation is all numbers between these values. Range: 0 ≤ V(c) ≤ 1568

Drawing the Graph

We know that the points ( 0, 0) and ( 16, 1568) are the minimum and maximum points of the function. Therefore, the graph will be the line that joins these points.