Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
Cumulative Standards Review

Exercise 17 Page 290

Begin by finding the width of the larger rectangle by using the formula for the area of a rectangle.

29 ft

Practice makes perfect

We will first find the width of Rectangle A. We will then find the side lengths of Rectangle B using the similarity of rectangles. Only then will we able to find the perimeter of Rectangle B.

Width of Rectangle A

We will first use the formula for the area of a rectangle to find the width of Rectangle A.

A= l * w
180= 20* w
9=w
w=9

Side Lengths of Rectangle B

Knowing the length of the larger rectangle's width, we can use the similarity between the figures to find the sides of Rectangle B. Let's call the sides of it x and y as shown below.

The similarity of the rectangles A and B allows us to create the following proportion. 9/x=20/y We can rearrange this equation to express one variable in terms of the other.

9/x=20/y
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Solve for y
9y/x=20
9y=20x
y=20x/9

Now, let's use the formula for calculating a rectangle's area once more. This time, however, we will use it with regards to Rectangle B. A=x* y By substituting the expression we just found for y and 45 for A into the formula, we can solve for x.

A=x* y
45=x* 20x/9
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Solve for x
45=20x^2/9
405=20x^2
20.25=x^2
x^2=20.25
x=4.5

One of the sides has a length of 4.5ft. To find the other length, we substitute this value back into the equation for y.

y=20x/9
y=20* 4.5/9
y=90/9
y=10

Rectangle B has a width of 4.5ft and length of 10ft.

Perimeter of Rectangle B

Finally, we can use these lengths to find the perimeter of Rectangle B.

P=2x+2y
P=2( 4.5)+2( 10)
P=9+20
P=29

The perimeter of rectangle B is 29ft.