Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
3. Solving Multi-Step Equations
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Exercise 50 Page 98

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

-5 1112

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality. In this case, we will start by eliminating fractions. First, we need to find their least common denominator. 2/3+n+6=3/4 ⟹ 2/3+n/1+6/1=3/4In this equation, our denominators are 1, 3, and 4. Therefore, the least common denominator is 12. To eliminate the fractions, we have to multiply both sides of the equation by 12. Then, we will solve for n.

2/3+n+6=3/4
(2/3+n+6)12=(3/4)12
2/3(12)+n(12)+6(12)=(3/4)12
2*12/3+n(12)+6(12)=3*12/4
24/3+12n+72=36/4
8+12n+72=9
12n+80=9
12n+80-80=9-80
12n=-71
n=-71/12
n=-71/12

The solution to the equation is n=- 7112. Although it is a perfectly valid solution, we can also rewrite it as a mixed number.

n=-71/12
n=-60+11/12
n=-(60/12+11/12)
n=-(5+11/12)
n=-5 1112

The proper notation for a mixed number makes our final solution n=-5 1112.