Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
3. Solving Multi-Step Equations
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Exercise 47 Page 98

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

3 516

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality. In this case, the variable terms are already on the left-hand side of the equation, so we will start by combining like terms and then isolating d-term.

3d+d-7=25/4
4d-7=25/4
4d-7+7=25/4+7
4d=25/4+7
4d=25/4+28/4
4d=53/4
1/4* 4d=1/4* 53/4
1d=1/4* 53/4
d=1/4* 53/4
d=53/16

Since 53 and 16 share no common factors, this is as simplified as this fraction can get. The solution to the equation is d= 5316. Although it is a perfectly valid solution, we can also rewrite it as a mixed number.

d=53/16
d=48+5/16
d=48/16+5/16
d=3+5/16
d=3 516

The proper notation for a mixed number makes our final solution d=3 516.