Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
3. Solving Multi-Step Equations
Continue to next subchapter

Exercise 45 Page 98

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

43 37

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality. In this case, we will start by moving the minus sign from the denominator to the front of the fraction. 6+v/- 8=4/7 ⟺ 6 -v/8=4/7 Now, we can eliminate the fractions by multiplying each side of the equation by their least common denominator. In this equation, our denominators are 8 and 7. Therefore, the least common denominator is 56. Let's multiply and solve for v.

6-v/8=4/7
(6-v/8)56=(4/7)56
6(56)-v/8(56)=(4/7)56
6(56)-56v/8=224/7
336-56v/8=224/7
336-7v=32
-7v=-304
v=- 304/- 7
v=304/7

There are no common factors between 304 and 7 so our answer is as simplified as possible. The solution to the equation is v= 3047. While it is a valid answer, we can also rewrite it as a mixed number. The easiest way to do this is to first use a calculator to find our whole number part of the mixed number.

v=304/7
v=43.428571 ...

Using 43, we can write our improper fraction as a mixed number.

v=304/7
v=43*7+3/7
v=43*7/7+3/7
v=43+3/7
v=43 37

The proper notation for a mixed number makes our final solution, v=43 37.