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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

3. Solving Multi-Step Equations

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Exercise 42 Page 98

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

6

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality. In this case, we will start by multiplying each side of the equation by 100 to clear the decimals.

1.12+1.25g=8.62

LHS * 100=RHS* 100

(1.12+1.25g)100=(8.62)100

Distribute 100

1.12(100)+1.25g(100)=(8.62)100

Multiply

112+125g=862

LHS-112=RHS-112

125g=750

.LHS /125.=.RHS /125.

g=6

The solution to the equation is g=6. We can check our solution by substituting it into the original equation.

1.12+1.25g=8.62

g= 6

1.12+1.25( 6)? =8.62

Multiply

1.12+7.5? =8.62

Add terms

8.62=8.62

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Lesson Check p.97

Practice and Problem-Solving Exercises p.98-100

Standardized Test Prep p.100

Mixed Review p.100