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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

3. Solving Multi-Step Equations

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Exercise 28 Page 98

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

2

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality. In this case, we need to start by using the Distributive Property to simplify the left-hand side of the equation.

n+5(n-1)=7

Distribute 5

n+(5)n-(5)1=7

Multiply

n+5n-5=7

Add terms

6n-5=7

LHS+5=RHS+5

6n-5+5=7+5

Add terms

6n=12

.LHS /6.=.RHS /6.

6n/6=12/6

MovePartNumRight

a* b/c=a/c* b

6/6n=12/6

a/a=1

n=2

The solution to the equation is n=2. We can check our solution by substituting it into the original equation.

n+5(n-1)=7

n= 2

2+5( 2-1)? =7

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Evaluate left-hand side

Subtract term

2+5(1)? =7

Identity Property of Multiplication

2+5? =7

Add terms

7=7

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Lesson Check p.97

Practice and Problem-Solving Exercises p.98-100

Standardized Test Prep p.100

Mixed Review p.100