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How does the given time relate to the time each person takes to paint the whole house?
How is this related to the fraction of a house each person paints per day?
When working together each person will still paint the same fraction they would paint individually.
How can you relate the fraction of the house painted when working together to the fraction of the house you are interested in?
Tim: 16
Tara: 13
Tim: d6
Tara: d3
In 1 Day: 12
In d Days: d2
Equation: d2=1
Solution: d=2
The problem says that Tim can paint a house in 6 days while Tara does it in 3. Then it asks us to find what fraction of the house each would paint in 1 day. Notice that 1 day is one sixth of the time Tim needs.
Now, we want to find what fraction of the house each person would paint in d days. Since Tim paints 16 of the house per day, in d days he would have painted d times that quantity.
Now we are asked what fraction of the house they would paint together in 1 day and in d days. For this we can add the fractions of the house they would paint individually, as each of them will be painting at the same pace they would be painting alone. Let's find this for 1 day first.
1/6+1/3
a/b=a * 2/b * 2
Multiply
Add fractions
a/b=.a /3./.b /3.
Divide by 3
Hence, if painting together they will paint 12 of the house in 1 day. Therefore, if each day painting together they paint 12 of the house, in d days they will paint d times that fraction. 1/2 * d = d/2 Thus, painting together they paint d2 of the house in d days.
Finally, we need to write an equation that we can solve to find the days they would need to paint the whole house working together. Since d2 is the part of the house they paint together in d days, they will finish painting one house when that expression is equal to 1.
LHS * 2=RHS* 2
a/2* 2 = a
Multiply
Hence, they would need 2 days to paint the whole house if working together.