Exercise 1 Page 97

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

4 1115

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality. In this case, the variable terms are already on the left-hand side of the equation, so we will start by combining the variable terms.

7p+8p-12=59

AddTerms

Add terms

15p-12=59

AddEqn

LHS+12=RHS+12

15p-12+12=59+12

AddTerms

Add terms

15p=71

DivEqn

.LHS /15.=.RHS /15.

p=71/15

The solution to the equation is p= 7115. We can check our solution by substituting it into the original equation.

7p+8p-12=59

Substitute

p= 71/15

7( 71/15)+8( 71/15)-12? =59

▼

Evaluate left-hand side

MoveLeftFacToNum

a*b/c= a* b/c

497/15+568/15-12? =59

AddFrac

Add fractions

1065/15-12? =59

CalcQuot

Calculate quotient

71-12? =59

SubTerm

Subtract term

59=59

Since the left-hand side is equal to the right-hand side, our solution is correct. Although p= 7115 is a perfectly valid solution, we can also rewrite it as a mixed number.

p=71/15

WriteSum

Write as a sum

p=60+11/15

WriteSumFrac

Write as a sum of fractions

p=60/15+11/15

CalcQuot

Calculate quotient

p=4+11/15

Rewrite

Rewrite 4+11/15 as 4 1115