Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
4. Solving Equations With Variables on Both Sides
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Exercise 54 Page 108

Start with an expression for the left-hand side and choose any negative number, then calculate the expression's value when x equals that negative number.

Example Solution: 2x+9=x+4

Practice makes perfect

We are going to write an equation that has a negative number as the solution and contains the variable x on both sides. We can start off with any linear expression for the left-hand side. 2x+9 Now let's choose that our solution will be x=-5. By substituting -5 for x into the equation, we can determine what the expression equals.

2x+9
2( -5)+9
-10+9
-1
This means that the expression 2x+9 needs to be equal to -1. 2x+9=-1 Let's find another expression that equals -1 when x=-5. The simplest way to do this is by writing an expression where a number n added to x equals -1. x+n=-1 To find n, we should substitute -5 for x.

x+n=-1
-5+n=-1
n=4

Therefore, we found another expression that equals -1 when x=-5. x+4 Since both expressions equal -1 when x=-5, we can set them equal to one another. This will be our equation. 2x+9= x+4 Let's check our solution just to make sure. To do this we will solve the equation using the Subtraction Property of Equality.

2x+9=x+4
2x=x-5
x=-5

As we can see, x is a negative number so our solution is correct. This is just one possible solution for this problem.