Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
8. Probability of Compound Events
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Exercise 32 Page 781

When events are dependent, we can find the probability using the formula P(AthenB) = P(A)* P(BafterA).

1/12

Practice makes perfect

Recall that the probability of an event is the ratio of favorable outcomes to possible outcomes. Probability=Favorable outcomes/Possible outcomes In this exercise, we have a bag containing 9 coins. 3& nickels & 2& pennies 3& dimes & 1& quarterWe want to draw a coin and then, without replacing it, we draw another one. Not replacing the first coin means that the number of possible outcomes for the second draw is reduced by 1. This also means that the events are dependent, so the following formula applies. P( Athen B) = P( A)* P( Bafter A) Let's take a closer look at the given compound event. P(dime then dime) This means that we first need to find the probability of drawing a dime. Then we need to find the probability of drawing another dime after the first dime. Let's find each probability one at a time.

P(dime)

There are 9 coins in the bag and 3 of them are dimes. P(A)=&P(dime) P(A)=& 3/9=1/3 Therefore, the probability of drawing a dime is 13.

P(dime after dime)

Now that we have already drawn one coin and did not replace it, the number of coins in the bag is reduced to 8. Because our first draw was a dime, the number of dimes did change – there are 2 of them left. P(BafterA)= &P(dimeafterdime) P(BafterA)= & 2/8=1/4 Therefore, the probability of drawing another dime after the first dime is 14.

P(dime then dime)

Finally, we can find the desired probability.

P(Athen B) = P(A)* P( BafterA)
P(AthenB) = 1/3 * 1/4
P(AthenB) = 1/12