Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
8. Probability of Compound Events
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Exercise 28 Page 781

When events are dependent, we can find the probability using the formula P(AthenB) = P(A)* P(BafterA).

1/12

Practice makes perfect

Recall that the probability of an event is the ratio of favorable outcomes to possible outcomes. Probability=Favorable outcomes/Possible outcomes In this exercise, we have a bag containing 9 coins. 3& nickels & 2& pennies 3& dimes & 1& quarterWe want to draw a coin and then, without replacing it, we draw another one. Not replacing the first coin means that the number of possible outcomes for the second draw is reduced by 1. This also means that the events are dependent, so the following formula applies. P( Athen B) = P( A)* P( Bafter A) Let's take a closer look at the given compound event. P( penny then dime) This means that we first need to find the probability of drawing a penny. Then we need to find the probability of drawing a dime after the penny. Let's find each probability one at a time.

P(penny)

There are 9 coins in the bag and 2 of them are pennies. Therefore, the probability of drawing a penny is 29. P( A)= &P( penny) P( A)= & 2/9

P(dime after penny)

Now that we have already drawn one coin and did not replace it, the number of coins in the bag is reduced to 8. Because our first draw was a penny, the number of dimes did not change – there are still 3 of them. Therefore, the probability of drawing a dime after the penny is 38. P(Bafter A)= &P(dimeafter penny) P(Bafter A)= & 3/8

P(penny then dime)

Finally, we can find the desired probability.

P( AthenB) = P( A)* P(Bafter A)
P(AthenB) = 2/9 * 3/8
P(AthenB) = 2*3/9*8
P(AthenB) = 1*3/9*4
P(AthenB) = 1*1/3*4
P(AthenB) = 1/12