Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
8. Probability of Compound Events
Continue to next subchapter

Exercise 27 Page 781

When events are dependent, we can find the probability using the formula P(AthenB) = P(A)* P(BafterA).

1/36

Practice makes perfect

Recall that the probability of an event is the ratio of favorable outcomes to possible outcomes. Probability=Favorable outcomes/Possible outcomes In this exercise, we have a bag containing 9 coins. 3& nickels & 2& pennies 3& dimes & 1& quarterWe want to draw a coin and then, without replacing it, we draw another one. Not replacing the first coin means that the number of possible outcomes for the second draw is reduced by 1. This also means that the events are dependent, so the following formula applies. P( Athen B) = P( A)* P( Bafter A) Let's take a closer look at the given compound event. P( quarter then penny) This means that we first need to find the probability of drawing a quarter. Then we need to find the probability of drawing a penny after the quarter. Let's find each probability one at a time.

P(quarter)

There are 9 coins in the bag and 1 of them is a quarter. Therefore, the probability of drawing a quarter is 19. P(A)=&P(quarter) P(A)=& 1/9

P(penny after quarter)

Now that we have already drawn one coin and did not replace it, the number of coins in the bag is reduced to 8. Because our first draw was a quarter, the number of pennies did not change – there are still 2 of them. Therefore, the probability of drawing a penny after the quarter is 14. P(BafterA)= &P(pennyafterquarter) P(BafterA)= & 2/8=1/4

P(quarter then penny)

Finally, we can find the desired probability.

P(AthenB) = P(A)* P(BafterA)
P(AthenB) = 1/9 * 1/4
P(AthenB) = 1/36