We are given the following weights of the scuba divers and we know that a tank weighs 15 kg.
85, 103, 94, 97, 88, 91, 104, 95
Each value in our data set is a weight of a particular scuba diver, increased by the weight of the tank.
100, 118, 109, 112, 103, 106, 119, 110
We want to find the , , and of this data set.
Mean
The mean of a data set is the sum of the values divided by the total number of values in the set. Let's start by calculating the sum of the given values.
100+118+109+112+103+106+119+110
= 877
There are 8 values in our set, so we have to divide the sum by 8.
Mean: 877/8=109.625
We can round the result to the nearest tenth.
Mean = 109.625
Mean ≈ 109.6
Median
When the data are arranged in numerical order, the median is the middle value — or the mean of the two middle values — in a set of data. Let's arrange the given values and find the median.
100, 103, 106, 109 | 110, 112, 118, 119
Since there are 8 values, there is no one middle value. Thus, for this exercise, the median is the mean of the two middle values.
Median: 109+110/2=109.5
Mode
The mode is the value or values that appear most often in a set of data.
Let's find the mode of the given values.
100, 103, 106, 109, 110, 112, 118, 119
Since the data set does not contain any repeated values, there is no mode.
Range
The range is the difference between the greatest and least values in a set of data.
100, 103, 106, 109, 110, 112, 118, 119
For our exercise, the greatest value is 119 and the least value is 100.
Range: 119-100=19
