Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
Chapter Test

Exercise 22 Page 791

Consider the formula for the number of combinations.

No, see solution.

Practice makes perfect

We are asked whether it is possible for r to be greater than n in the formula for the number of combinations, _nC_r. To answer this question, we will first recall the formula. _nC_r = n!/r!( n- r)! Let's assume that r is greater than n and take a closer look at the product in the denominator of the formula. _nC_r = n!/r! (n-r)! We will now consider the expression (n-r)!. Because n is less than r, the expresion n-r is less than 0. n < r ⇕ n-r < 0 This means that (n-r)! is the factorial of negative values of n-r. However, factorials are not defined for negative numbers. This follows that r cannot be greater than n in the formula for _nC_r.

Interpretation and Alternative Approach

Recall that _nC_r represents the number of possible ways we can choose r out of n objects at a time without regard to order. Let's again assume that r is greater than n. Although it is not possible for the formula _nC_r, we can still say that there are possible ways we can choose r out of n objects for r greater than n. r> n ⇒ _nC_r = 0 For example, let's consider r = 5 and n = 3. We want to choose 5 out of 3 fruits to make a smoothie.

There are possible ways we can choose 5 out of 3 fruits.