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What is the probability of a compound event when the events are mutually exclusive?
Yes, see solution.
We are given the formula for the probability of a compound event. P(AorB) = P(A) + P(B) - P(AandB) This formula is used for calculating the probability of overlapping events. We want to determine whether we can also use it to calculate the probability of mutually exclusive events. Let's use a Venn diagram to illustrate the probabilities of overlapping and mutually exclusive events.
P(AandB)= 0
Subtract term
Notice that we obtained the formula for the probability of mutually exclusive events. This means that we can use the given formula for both overlapping events and mutually exclusive events.
Let's consider a scenario that we randomly draw a 2 or a 10 from a standard deck of cards. Since a card cannot be both a 2 and a 10 at the same time, these are mutually exclusive events. Let's draw these events with a Venn diagram!
Since there are 52 cards in a deck, and 4 of each 2 and of each 10, we will divide 4 by 52 to find the probability of each individual event. ccc Drawing a2: && Drawing a10: [0.5em] P(2) = 4/52 && P(10) = 4/52 We know that there are no favorable outcomes for both events. Therefore, the probability of drawing a card that is both a 2 and a 10 is 0. P(2 and10) = 0 Now we will find the probability that we draw either a 2 or a 10. To do so, let's use the given formula.
Substitute values
Subtract term
Add fractions
We can confirm this probability seeing that 8 out of the 52 cards are our favorable outcomes. This probability can be further simplified to 213.