Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
6. Inverse Variation
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Exercise 52 Page 704

Use the Product of Powers Property and cancel out common factors.

196

Practice makes perfect

We want to find the value of the given expression. 7^3 * 2^5/7 * 2^3 We will begin by using the Product of Powers Property and canceling out any common factors.

7^3 * 2^5/7 * 2^3
7^(1+2) * 2^(2+3)/7 * 2^3
7^1 * 7^2 * 2^2 * 2^3/7 * 2^3
7 * 7^2 * 2^2 * 2^3/7 * 2^3
7 * 7^2 * 2^2 * 2^3/7 * 2^3
7^2 * 2^2
49 * 4
196