Substitute the given solutions into the radical equation one at a time. If a true statement is not obtained, the solution is extraneous.
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Practice makes perfect
We have a radical equation and are asked which of the given solutions, if any, are extraneous for the equation.
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Equation & & Solutions
- t = sqrt(-6 t -5) & & t=-5, t=-1To answer this question, we will substitute both solutions into the equation one at a time and check whether or not we obtain a true statement. Let's start by substituting t=-5.
Since we obtained a true statement, we can conclude that t=-5 is not an extraneous solution. Let's repeat the process, this time substituting t=-1 into the equation.
