Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
2. Simplifying Radicals
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Exercise 69 Page 624

8sqrt(6a)/3a

Practice makes perfect

We want to simplify a radical expression. To do so we will assume that a>0, otherwise the given expression would not be defined. 16a/sqrt(6a^3) Let's recall the Multiplication Property of Square Roots and the Division Property of Square Roots. sqrt(ab)&=sqrt(a) * sqrt(b), for a≥ 0,b≥ 0 sqrt(a/b)&=sqrt(a)/sqrt(b), for a≥ 0,b> 0 Let's use these properties for our expression.

16a/sqrt(6a^3)
16* a/sqrt(6a* a^2)
16* a/sqrt(6a)* sqrt(a^2)
â–¼
Simplify factors
16* a/sqrt(6a)* a
16* a/sqrt(6a)* a
16/sqrt(6a)

Now that we have simplified the factors as much as possible, we need to rationalize the denominator. To do this, we will multiply the numerator and denominator by a square root that will eliminate the radical in the denominator.

16/sqrt(6a)
16sqrt(6a)/sqrt(6a)sqrt(6a)
16sqrt(6a)/6a
2(8sqrt(6a))/2(3a)
8sqrt(6a)/3a