Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
2. Simplifying Radicals
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Exercise 41 Page 623

77a/2

Practice makes perfect

We want to simplify a radical expression. To do so we will assume that a>0, otherwise the given expression would not be defined. 11sqrt(49a^5/4a^3)Let's recall the Multiplication Property of Square Roots and the Division Property of Square Roots. sqrt(ab)&=sqrt(a) * sqrt(b), for a≥ 0,b≥ 0 [0.4em] sqrt(a/b)&=sqrt(a)/sqrt(b), for a≥ 0,b> 0 Let's use these properties for our expression.

11sqrt(49a^5/4a^3)
11sqrt(49a^5)/sqrt(4a^3)
11sqrt(49* a^2* a^2* a)/sqrt(4* a^2* a)
11sqrt(49)*sqrt(a^2)* sqrt(a^2)*sqrt(a)/sqrt(4)* sqrt(a^2)*sqrt(a)
â–¼
Simplify Factors
117* sqrt(a^2)* sqrt(a^2)* sqrt(a)/2* sqrt(a^2)* sqrt(a)
117* a* a* sqrt(a)/2* a* sqrt(a)
117* a* a* sqrt(a)/2* a* sqrt(a)
117a/2
77a/2