Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
1. Variables and Expressions
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Exercise 23 Page 7

Try to break the expression down into terms and operations, then break those terms into factors.

Example Solution: The difference of 15 and the quotient of 1.5 and a number d.

Practice makes perfect

Our approach to representing the given algebraic expression verbally will be to break it down into terms and operations. 15 - 1.5/dIn this expression, the second term is being subtracted from the first one. Let's break it down into more digestible pieces.

Algebraic Term Verbal Translation
d a number d
1.5/d ⇔ 1.5÷ d the quotient of 1.5 and d
- the difference of ... and ...

Now that we have translated each of the pieces, let's bring it all together. The quotient is subtracted from the number 15, thus it should be the second term in the difference of ... and ... expression. & 15 - 1.5/d [0.5em] & The difference of 15 and the quotient of 1.5 & and a number d