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Consider how multiplying or dividing the given values could lead to the desired result.
Example Solution: \text{-}\dfrac {3yz}{2x}
There are many expressions we can create with the given values of x, y, and z to obtain a result of 1. We have that x= -3, y= -2, and z= -1. For our expression, we will arbitrarily choose to create a fraction. Now, for example, we can let the numerator of the fraction be 3yz.
3yz= 3( - 2)( - 1) = 6
From here, we can think about what we might divide 6 by to end with 1. Since the result needs to be positive, the number we are looking for is positive. The result also is a whole number. Consider a few possibilities.
| Possible Number | Division | Result |
|---|---|---|
| 1 | 6 ÷ 1 | 6 |
| 2 | 6 ÷ 2 | 3 |
| 3 | 6 ÷ 3 | 2 |
| 6 | 6 ÷ 6 | 1 |
That means that the denominator of our fraction must be 6. Notice that if we multiply -2 by x we will obtain exactly 6. -2 * x =- 2( - 3) = 6 Knowing that, we can complete our expression. \begin{gathered} \dfrac {3yz}{\text{-}2x} \quad \Leftrightarrow \quad \text{-}\dfrac{3yz}{2x} \end{gathered} We can verify that this works by substituting the given values into our expression.
Substitute values
Put minus sign in denominator
(- a)(- b)=a* b
Multiply
Calculate quotient
Since the obtained value is 1, the expression is correct. Keep in mind that this is just one possible answer out of infinitely many.