McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
3. Similar Triangles
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Exercise 33 Page 567

See solution.

Practice makes perfect

Let's consider a line l and four points on it.

We have that ∠ C ≅ ∠ C' since all right angles are congruent. Now, notice that BC∥ B'C' and l is a transversal. Then, by the Corresponding Angles Theorem we get ∠ B ≅ ∠ B'.

In consequence, the Angle-Angle (AA) Similarity Postulate leads us to conclude that △ ABC ~ △ A'B'C'. This allows us to write the following proportion. BC/B'C' = AC/A'C' Finally, let's rewrite the proportion above in an equivalent way. BC/AC = B'C'/A'C' = Rise/Run = m We have seen that no matter the points we pick to find the slope of a line, it will always be the same.

The slope of line l through A and B, which is BCAC, is equal to B'C'A'C', the slope of the line l through A' and B'.