McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
3. Similar Triangles
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Exercise 24 Page 566

Create a proportion using the lengths of similar triangles.

10.75 meters

Practice makes perfect

Bartolo wants to find a height of a tree by using a hypsometer. A hypsometer uses the properties of similar triangles to estimate a height of an object. Let's take a look at the diagram to find similar triangles.

We can see that segments DE and GH are perpendicular to the ground. This means DE and GH are parallel. Therefore, ∠ E and ∠ G are congruent angles. We also know that ∠ F and ∠ H are right angles. Now, let's recall an Angle-Angle (AA) Similarity.

Angle-Angle (AA) Similarity

If two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.

By this postulate, we know that △ DEF is similar to △ FGH. △ DEF ~ △ FGH Recall that in similar triangles corresponding sides are proportional. With this information, we can create a proportion using the given lengths of these triangles. 15/10=x/6 Now, we will solve the above equation for x using cross multiplication.
15/10=x/6
15*6=10* x
90=10x
9=x
x=9
The value of x is 9 m. However, we need to remember that the height of a tree is the value of x plus the Bartolo's height, which is 1.75 m. 9+ 1.75=10.75 The height of this tree is 10.75 meters.