body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

McGraw Hill Integrated II, 2012

MH

McGraw Hill Integrated II, 2012 View details

7. Scale Drawings and Models

Finish the assignment

Continue to next subchapter

Exercise 27 Page 605

BD is the median of AC.

D

Practice makes perfect

We want to find the value of AC in the given diagram.

We are given that AD=3x+5 and CD=5x-1. Also, we know that BD is the median of AC. AD=DC ⇒ 3x+5=5x-1 Let's solve the above equation for x.

3x+5=5x-1

▼

Solve for x

LHS-5x=RHS-5x

- 2x+5=- 1

LHS-5=RHS-5

- 2x=- 6

.LHS /- 2.=.RHS /- 2.

x=3

Knowing the value of x, we can find the length of one of the segments of AC. Let's find AD.

AD=3x+5

x= 3

AD=3( 3)+5

▼

Evaluate

Multiply

AD = 9 + 5

Add terms

AD=14

Since BD is the median of AC, to find the length of AC we need to multiply the length of AD by 2. AC = AD * 2 ⇒ AC = 28 We see that the answer is D.

Subchapter links

Exercises p.602-605