McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
7. Scale Drawings and Models
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Exercise 20 Page 604

Practice makes perfect
a First, we are asked to draw △ ABC with the right angle at vertex B and an altitude BD.

Next, we will draw two more right triangles MNP and WXY with the right angles at vertices N and X respectively. In each triangle we will draw its altitude from its right angle.

b In this part we are asked to measure and record the indicated angles. To do this, we will use a protractor. Let's start with △ ABC.

We can measure the rest of the angles in the same way.

Now we can complete the table using the angle measures we found.

Angle Measures
△ ABC △ ABC △ BDC △ ADB
ABC 90^(∘) BDC 90^(∘) ADB 90^(∘)
A 45^(∘) CBD 45^(∘) BAD 45^(∘)
C 45^(∘) DCB 45^(∘) DBA 45^(∘)
△ MNP △ MNP △ NQP △ MQN
MNP 90^(∘) NQP 90^(∘) MQN 90^(∘)
M 52^(∘) PNQ 52^(∘) NMQ 52^(∘)
P 38^(∘) QPN 38^(∘) QNM 38^(∘)
△ WXY △ WXY △ WZX △ XZY
WXY 90^(∘) WZX 90^(∘) XZY 90^(∘)
W 60^(∘) XWZ 60^(∘) YXZ 60^(∘)
Y 30^(∘) ZXW 30^(∘) ZYX 30^(∘)
c Looking at the table we made in Part B, we can see that all three triangles in each row are similar by the Angle-Angle Similarity Theorem. Therefore, we can assume that if an altitude in a right triangle is drawn from a right angle, then it divides this triangle into two triangles that are similar to the original one.