McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
7. Scale Drawings and Models
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Exercise 4 Page 602

Evaluate the quotients of the corresponding dimensions, choose the greater result, and round it to the nearest integer.

Example Solution: 1in.=4m
A scale drawing:

Practice makes perfect
We are given that a volleyball court has dimensions of 9meters* 18meters and asked to choose an appropriate scale of the court to fit on an index card of dimensions of 3inches*5inches. First, we will evaluate the quotients of the corresponding dimensions. &9meters/3inches=3meters per inch &18meters/5inches=3.6meters per inch To choose an appropriate scale, we will round the greater of the results to the nearest integer that is greater than this number. Since 3.6>3, we will round 3.6 to the nearest integer that is not less than this number. 3.6≈4 Therefore, an appropriate scale of the court will be 1in.=4m. Notice that this is only a sample answer. Next, we are asked to construct a scale drawing of the court. We will start with evaluating the width, which we will represent with w. To do this, we will use a scale we just found.
1/4=w/9
Solve for w
1*9=4* w
9=4w
9/4=w
2.25=w
w=2.25
The width of a scale drawing of the court will be 2.25 inches. We will find its length in the same way. Let l represent this dimension.
1/4=l/18
Solve for l
1*18=4* l
18=4l
18/4=l
4.5=l
l=4.5
The length of a scale drawing of the court will be 4.5 inches. Using these dimensions, we can make an appropriate drawing.