Let's begin with plotting the given points in the coordinate plane. Since the point of intersection of diagonals, let's call it P, is not between the given vertices, let's call them A and B, the distance between these vertices is a side.
Recall that in a parallelogram diagonals bisect each other. This means that the distance between B and P is the same as the distance between P and the fourth vertex, D. Since we can see that PB is 3, the fourth vertex will be 3 units to the left from the point of intersection.
To find the third vertex, C, we will also use the fact that the distance between A and P is the same as the distance between P and C. To get to the point P from the point A, we need to move down by 3 units and then move 2 units left. Let's repeat these moves starting in point P.
Now, we have all four vertices of this parallelogram.
The remaining vertices are located in (-2,-2) and (-3,1).
