McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
3. Tests for Parallelograms
Continue to next subchapter

Exercise 20 Page 500

If a diagonal divides a quadrilateral into two congruent triangles, then the quadrilateral is a parallelogram.

x=30
y=15.5

Practice makes perfect

We want to find the values of x and y for which the given quadrilateral is a parallelogram. Recall that if a diagonal divides a quadrilateral into two congruent triangles, then the quadrilateral is a parallelogram.

Note that one side is common for both triangles and that there are two congruent angles. For the two triangles to be congruent, we need the angles with measures 4x-8 and 8y-12 to be congruent, and the angles with measures y-8 and 14x to also be congruent. With this, we can write a system of equations. 4x-8=8y-12 & (I) y-8= 14x & (II) We will solve the system by using the Substitution Method. Let's start by isolating the x-variable in Equation (II).

4x-8=8y-12 y-8= 14x
â–¼
(II): Solve for x
4x-8=8y-12 (y-8)4=x
4x-8=8y-12 4y-32=x
4x-8=8y-12 x=4y-32

Now that x is isolated in Equation (II), we will substitute x=4y-32 in Equation (I), and solve for y.

4x-8=8y-12 x=4y-32
4( 4y-32)-8=8y-12 x=4y-32
â–¼
(I): Solve for y
16y-128-8=8y-12 x=4y-32
16y-136=8y-12 x=4y-32
8y-136=-12 x=4y-32
8y=124 x=4y-32
y=15.5 x=4y-32

We found that y=15.5. Finally, we will find the value of x by substituting this value in Equation (II).

y=15.5 x=4y-32
y=15.5 x=4( 15.5)-32
y=15.5 x=62-32
y=15.5 x=30