Mid-Chapter Quiz
Sign In
Compare the angles with ∠A.
See solution.
We are given two parallelograms with a common vertex and we are asked to show that angles ∠F and ∠D are congruent.
Let's compare both angles to ∠A.
Opposite angles in parallelogram HACD are also congruent. ∠A≅ ∠D These observations let us write a chain of congruent angles. ∠F≅ ∠A≅ ∠D Using the transitive property of congruence, we can conclude that angles ∠F and ∠D are congruent. We can summarize the process above in a two-column proof.
2 &Given:&& GFBAis a parallelogram & && HACDis a parallelogram &Prove:&& ∠F≅∠D Proof:
| Statements | Reasons |
| GFBA is a parallelogram | Given |
| ∠F≅∠A | Opposite angles (Theorem 6.4) |
| HACD is a parallelogram | Given |
| ∠A≅∠D | Opposite angles (Theorem 6.4) |
| ∠F≅∠D | Transitive Property of congruence |