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Consider the Hinge Theorem.
5/3< x< 8
For the given triangles, we will find the range of possible values for x.
In order to do that, we will use the Hinge Theorem to compare the side lengths.
Applying the theorem, we can write an inequality for the side lengths. 37^(∘) > 27 ^(∘) ⇒ 2x+3 > 3x-5 Let's solve the inequality for x.
LHS+5>RHS+5
LHS-2x>RHS-2x
Rearrange inequality
All x-values less than 8 will work. Additionally, notice that 3x-5 and 2x+3 must be greater than 0. cc Inequality II & Inequality III [0.5em] 3x-5 >0 & 2x+3 >0 ⇓ & ⇓ x > 5/3 & x >- 3/2 Since Inequality III contains values that make 3x-5 negative, we can disregard it. Therefore, 53 is the lower limit and 8 is the upper limit of x. Inequality I:&& & x < 8 [0.5em] Inequality II:&& 5/3< & x [0.5em] Combined:&& 5/3<& x< 8