McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
6. Inequalities in Two Triangles
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Exercise 5 Page 458

Practice makes perfect
a Let's sketch the triangles appearing in the picture.

We are asked to find congruent segments.

Congruent Segments Justification
AB≅DE The length of both of these segments is the height of the swing.
AC≅DF The length of both of these segments is the length of the rope of the swing.
b Our result in Part A shows that two sides of triangle △ ABC is congruent to two sides of triangle △ DEF.

Segment EF is longer than segment BC, because the child on the first picture is closer to the starting position than in the second picture. EF> BC According to the Converse of the Hinge Theorem, this means that the included angle measure in triangle △ DEF is greater than the included angle measure in triangle △ ABC. m ∠ D>m ∠ A