6. Inequalities in Two Triangles
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Consider the height of the swing and the length of the rope.
Consider the position of the swing.
AB≅DE
AC≅DF
m∠D>m∠A, see solution.
Let's sketch the triangles appearing in the picture.
We are asked to find congruent segments.
| Congruent Segments | Justification |
|---|---|
| AB≅DE | The length of both of these segments is the height of the swing. |
| AC≅DF | The length of both of these segments is the length of the rope of the swing. |
Our result in Part A shows that two sides of triangle â–³ ABC is congruent to two sides of triangle â–³ DEF.
Segment EF is longer than segment BC, because the child on the first picture is closer to the starting position than in the second picture. EF> BC According to the Converse of the Hinge Theorem, this means that the included angle measure in triangle △ DEF is greater than the included angle measure in triangle △ ABC. m ∠D>m ∠A