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Use the Triangle Angle Sum Theorem. Then consider Theorem 5.10 about Angle-Side Relationships in Triangles.
Angles: ∠P, ∠Q, ∠M
Sides: MQ, PM, PQ
To solve this exercise we will begin by breaking down the given the diagram. Here, we are given the expressions for the interior angles of â–³ MPQ.
By the Triangle Angle Sum Theorem, we know that the sum of these measures is 180^(∘).
(2x+3)+(x-1)+(x+6)=180
Remove parentheses
Add and subtract terms
LHS-8=RHS-8
.LHS /4.=.RHS /4.
Now that we know the value of x, we can find the measure of each angle.
| Expression | Substitution | Measure |
|---|---|---|
| m∠M = (2x+3)^(∘) | (2( 43)+3)^(∘) | 89^(∘) |
| m∠P = (x-1)^(∘) | ( 43-1)^(∘) | 42^(∘) |
| m∠Q = (x+6)^(∘) | ( 43+6)^(∘) | 49^(∘) |
Comparing the angle measures, we can see that the smallest angle is ∠P followed by ∠Q and ∠M. ∠P, ∠Q, ∠M Next, let's consider Theorem 5.10 about Angle-Side Relationships in Triangles.
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Angle-Side Relationships in Triangles |
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If one angle of a triangle has a greater measure than another angle, then the side opposite the greater angle is longer than the side opposite the lesser angle. |
Now, by this theorem, we will look for the corresponding opposite sides. cc Angle & Opposite Side [0.5em] ∠P & MQ [0.5em] ∠Q & PM [0.5em] ∠M & PQ From here, we can list the sides in order from smallest to largest. MQ < PM < PQ