3. Proving Triangles Congruent-SSS, SAS
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Use the definition of a perpendicular bisector and notice that BD is a common side for both triangles.
Statements
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Reasons
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1. BD⊥AC and BD bisects AC
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1. Given
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2. AD≅CD
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2. Definition of segment bisector
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3. m∠BDA=90^(∘) = m∠BDC
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3. Definition of perpendicular segments
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4. ∠BDA ≅ ∠BDC
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4. Definition of congruent angles
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5. BD≅BD
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5. Reflexive Property of Congruent Segments
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6. △ ABD ≅ △ CBD
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6. Side-Angle-Side (SAS) Congruence Postulate
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We are given that BD⊥ AC, which implies that m∠ BDA= 90^(∘) = m∠ BDC. Also, since BD bisects AC we get AD≅CD. Let's highlight these facts in the given diagram.
Notice that side BD is common for both △ ABD and △ CDB. By the Reflexive Property of Congruent Segments we have BD ≅ BD. Next, let's summarize all we know about the triangles above. cc AD≅CD & Side ∠BDA≅∠BDC & Included Angle BD≅BD & Side Therefore, by the Side-Angle-Side (SAS) Congruence Postulate we conclude △ ABD ≅ △ CBD. Finally, let's write the two-column proof table.
Statements
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Reasons
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1. BD⊥AC and BD bisects AC
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1. Given
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2. AD≅CD
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2. Definition of segment bisector
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3. m∠BDA=90^(∘) = m∠BDC
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3. Definition of perpendicular segments
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4. ∠BDA ≅ ∠BDC
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4. Definition of congruent angles
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5. BD≅BD
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5. Reflexive Property of Congruent Segments
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6. △ ABD ≅ △ CBD
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6. Side-Angle-Side (SAS) Congruence Postulate
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