McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
3. Proving Triangles Congruent-SSS, SAS
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Exercise 12 Page 358

Use the definition of a perpendicular bisector and notice that BD is a common side for both triangles.

Statements
Reasons
1.
BD⊥AC and BD bisects AC
1.
Given
2.
AD≅CD
2.
Definition of segment bisector
3.
m∠BDA=90^(∘) = m∠BDC
3.
Definition of perpendicular segments
4.
∠BDA ≅ ∠BDC
4.
Definition of congruent angles
5.
BD≅BD
5.
Reflexive Property of Congruent Segments
6.
△ ABD ≅ △ CBD
6.
Side-Angle-Side (SAS) Congruence Postulate
Practice makes perfect

We are given that BD⊥ AC, which implies that m∠ BDA= 90^(∘) = m∠ BDC. Also, since BD bisects AC we get AD≅CD. Let's highlight these facts in the given diagram.

Notice that side BD is common for both △ ABD and △ CDB. By the Reflexive Property of Congruent Segments we have BD ≅ BD. Next, let's summarize all we know about the triangles above. cc AD≅CD & Side ∠BDA≅∠BDC & Included Angle BD≅BD & Side Therefore, by the Side-Angle-Side (SAS) Congruence Postulate we conclude △ ABD ≅ △ CBD. Finally, let's write the two-column proof table.

Statements
Reasons
1.
BD⊥AC and BD bisects AC
1.
Given
2.
AD≅CD
2.
Definition of segment bisector
3.
m∠BDA=90^(∘) = m∠BDC
3.
Definition of perpendicular segments
4.
∠BDA ≅ ∠BDC
4.
Definition of congruent angles
5.
BD≅BD
5.
Reflexive Property of Congruent Segments
6.
△ ABD ≅ △ CBD
6.
Side-Angle-Side (SAS) Congruence Postulate