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We can now connect them.
If two figures are a reflection of one another, then their corresponding sides are the same length. This suggests that the triangles are congruent. We can set the following conjecture. Conjecture: △ ABC ≅ △ XYZ
d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2)
Let's find the measure of AB by substituting the coordinates of points A and B in the formula.
Substitute ( -3,-5) & ( -1,-1)
Similarly, let's find the measure of XY.
Substitute ( 5,-5) & ( 3,-1)
Consequently, we have AB ≅ XY. The lengths of the remaining sides are summarized in the table below.
| Side | Distance | Measure |
|---|---|---|
| AC | AC = sqrt((-1-(-3))^2 + (-5-(-5))^2) | 2 |
| XZ | XZ = sqrt((3-5)^2 + (-5-(-5))^2) | 2 |
| BC | BC = sqrt((-1-(-1))^2 + (-5-(-1))^2) | 4 |
| YZ | YZ = sqrt((3-3)^2 + (-5-(-1))^2) | 4 |
We got AC≅XZ and BC≅YZ. Therefore, by the Side-Side-Side (SSS) Congruence Postulate we get △ ABC ≅ △ XYZ.