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Use the definition of congruent polygons and the Transitive Property of Congruence.
See solution.
Let's begin by recalling what the Transitive Property of Congruence states. After this, we can write a paragraph proof!
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If △ ABC ≅ △ EFG and △ EFG ≅ △ JKL, then △ ABC≅ △ JKL. |
| △ ABC ≅ △ EFG | △ EFG ≅ △ JKL |
|---|---|
| ∠ A≅ ∠ E | ∠ E≅ ∠ J |
| ∠ B≅ ∠ F | ∠ F≅ ∠ K |
| ∠ C ≅ ∠ G | ∠ G ≅ ∠ L |
| A B ≅ E F | E F ≅ J K |
| B C ≅ F G | F G ≅ K L |
| A C ≅ E G | E G ≅ J L |
By applying the Transitive Property of Congruence on each row of the table, we obtain the following congruence relations. ccc ∠ A≅ ∠ J & & A B ≅ J K ∠ B≅ ∠ K & and & B C ≅ K L ∠ C ≅ ∠ L & & A C ≅ J L Next, by the definition of congruent polygons we conclude that △ A B C ≅ △ J K L.
Given: & △ ABC ≅ △ EFG and △ EFG ≅ △ JKL Prove: & △ ABC≅ △ JKL Proof: Since △ ABC ≅ △ EFG and by the definition of congruent polygons, we get ∠ A ≅ ∠ E, ∠ B ≅ ∠ F, ∠ C ≅ ∠ G, AB ≅ EF, BC ≅ FG, and AC ≅ EG. Similarly, since △ EFG ≅ △ JKL we obtain ∠ E ≅ ∠ J, ∠ F ≅ ∠ K, ∠ G ≅ ∠ L, EF ≅ JK, FG ≅ KL, and EG ≅ JL.
Next, by using the Transitive Property of Congruence we get that ∠ A ≅ ∠ J, ∠ B ≅ ∠ K, ∠ C ≅ ∠ L, AB ≅ JK, BC ≅ KL, AC ≅ JL. Finally, by the definition of congruent polygons, we conclude that △ ABC≅ △ JKL.
For understanding, outside of a strict math concept, let's consider the Transitive Property of Congruence using relationships we have with our friends!
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If Julio's headphones are the same size as Michelle's headphones, and Bianca's headphones are the same size as Michelle's headphones, then Julio and Bianca's headphones are the same size. |