McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
1. Solving Quadratic Equations by Factoring
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Exercise 69 Page 175

Area of a triangle is the half of the product of its base and height.

13 cm

Practice makes perfect

Area of a triangle is the half of the product of its base and height.

Let's find the area of the triangle above. A=(x+7)(x-2)/2 We know that the area of the triangle is 26 cm^2. By substituting 26 for A in the equation above, we can start to solve the equation for x.

A=(x+7)(x-2)/2
26=(x+7)(x-2)/2
â–¼
Simplify
52=(x+7)(x-2)
52=x(x+7)-2(x+7)
52=x^2+7x-2(x+7)
52=x^2+7x-2x-14
52=x^2+5x-14
0=x^2+5x-66
x^2+5x-66=0
â–¼
Factorize
x^2-6x+11x-66=0
x(x-6)+11x-66=0
x(x-6)+11(x-6)=0
(x+11)(x-6)=0
â–¼
Solve using the Zero Product Property
lx+11=0 x-6=0
lx=-11 x-6=0
lx=-11 x=6

The value of x can be either -11 or 6. Because the measures of the base and height cannot be negative, the value of x must be 6. With this, we can find length of base. Base: x+7 ⇒ 6+7=13 Therefore, the length of the base is 13 cm.