McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
1. Solving Quadratic Equations by Factoring
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Exercise 66 Page 175

To find the price that produces profit, begin by finding the price in which the profit is zero.

Price ($): 9.25 < x < 313.752

Practice makes perfect

To find the price of the Web sites that produces profit, we will begin by finding the price of the Web sites in which the profit is zero. We will begin by substituting P(x)=0 in the given function. Then we will continue with writing the terms on the left-hand side.

P(x)=- 16x^2+368x-2035
0=- 16x^2+368x-2035
â–¼
Write the terms on the LHS
16x^2=368x-2035
16x^2-368x+2035=0
16x^2-368x+2035=0
Now we will solve the equation. Because the leading coefficient is not 1 and we cannot factor it out, we will use the Quadratic Formula to find the zeros of the equation. ax^2+ bx+ c=0 ⇔ x=- b± sqrt(b^2-4 a c)/2 a In our case, a= 16, b= -368, and c= 2035. Let's substitute these values into the formula and find the zeros.

x=- b±sqrt(b^2-4ac)/2a
x=- ( -368)±sqrt(( - 368)^2-4( 16)( 2035))/2( 16)
â–¼
Solve for x and Simplify
x=368±sqrt((- 368)^2-4(16)(2035))/2(16)
x=368±sqrt(135 424-4(16)(2035))/2(16)
x=368±sqrt(135 424-130 240)/32
x=368±sqrt(5184)/32
x=368± 72/32
x=11.5± 2.25

Therefore, we have two roots as x=9.25 and x=13.75. Notice that the leading coefficient is negative. This means that the graph of the function opens downward and it has a maximum value. Therefore, P(x) is positive for 9.25 < x < 13.75. When the price is between this range, the company will earn profit.