Exercise 60 Page 175

Make sure you rewrite the equation leaving all the terms on one side.

x=5/3 and x= 1/9

Practice makes perfect

We want to solve the given equation by factoring.

Factoring

Let's start by writing all the terms on one side of the equals sign.

27x^2 +5 = 48x

SubEqn

LHS-48x=RHS-48x

27x^2-48x +5 = 0

WriteDiff

Write as a difference

27x^2-3x-45x +5 = 0

▼

Factor out 3x & - 5

FactorOut

Factor out 3x

3x(9x-1)-45x +5 = 0

FactorOut

Factor out - 5

3x(9x-1)-5(9x -1) = 0

FactorOut

Factor out (9x-1)

(3x-5)(9x-1)=0

Solving

To solve this equation, we will apply the Zero Product Property.

(3x-5)(9x-1)=0

ZeroProdProp

Use the Zero Product Property

lc3x-5=0 & (I) 9x-1=0 & (II)

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(I): Solve for x

AddEqn

(I): LHS+5=RHS+5

l3x=5 9x-1=0

DivEqn

(I): .LHS /3.=.RHS /3.

lx= 53 9x-1=0

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(II): Solve for x

AddEqn

(II): LHS+1=RHS+1

lx= 53 9x=1

DivEqn

(II): .LHS /9.=.RHS /9.

lx_1= 53 x_2= 19

Subchapter links

Exercises p.174-177

100

101

102

103

Exercise 60 Page 175

Hints

Check the answer

Practice exercises

Asses your skill

Factoring

Solving