McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
1. Solving Quadratic Equations by Factoring
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Exercise 57 Page 175

Use the given roots to write the equation in factored form. Then multiply and simplify to obtain the standard form.

Example Solution: 25x^2-100x+51=0

Practice makes perfect

We can write a quadratic equation in factored form using the given roots. Then we will change it to standard form by multiplying the factors. Factored Form:& a(x-p)(x-q)=0 Standard Form:& ax^2+bx+c=0 In the factored form, p and q are the roots of the equation. Since we are told the roots are 3.4 and 0.6, we can partially write the factored form of our equation. a( x- 3.4 ) ( x-0.6 )=0 Since a does not have any effect on the roots, we can choose any value. For simplicity and in order to have integer coefficients, we will let a=100. This will allow us to eliminate the decimals when we distribute. 100( x- 3.4 ) ( x-0.6 )=0 Finally, let's use the Distributive Property to obtain the standard form.

100( x- 3.4 ) ( x-0.6 )=0
â–¼
Distribute 100
10(10)( x- 3.4 ) ( x-0.6 )=0
10( x- 3.4 ) (10)( x-0.6 )=0
(10x-34) (10)( x-0.6 )=0
(10x-34)(10x-6)=0
â–¼
Multiply parentheses
10x(10x-6)-34(10x-6)=0
100x^2-60x-34(10x-6)=0
100x^2-60x-340x+204=0
100x^2-400x+204=0
25x^2-100x+51=0

Please note that this is just one example of a quadratic function that satisfies the given requirements.