McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
1. Solving Quadratic Equations by Factoring
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Exercise 26 Page 174

Try to rewrite the middle term, bx, as two terms.

(x+5)(x+8)

Practice makes perfect

To factor a trinomial with a leading coefficient of one, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term. x^2+13x+40 In this case, we have 40. This is a positive number, so for the product of the constant terms in the factors to be positive, these constants must have the same sign (both positive or both negative.)

Factor Constants Product of Constants
1 and 40 40
-1 and - 40 40
2 and 20 40
- 2 and - 20 40
4 and 10 40
- 4 and - 10 40
5 and 8 40
- 5 and - 8 40

Next, let's consider the coefficient of the linear term. x^2+13x+40 For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, 13.

Factors Sum of Factors
1 and 40 41
-1 and - 40 - 41
2 and 20 22
- 2 and - 20 - 22
4 and 10 14
- 4 and - 10 - 14
5 and 8 13
- 5 and - 8 - 13

We found the factors whose product is 40 and whose sum is 13. x^2+13x+40 ⇔ (x+5)(x+8)