Start by identifying a and b. Recall that for the vertex, the x-coordinate is - b2a and the y-coordinate is f(- b2a).
Vertex: ( 52,- 94) Maximum or Minimum: Minimum
For a quadratic function f(x)=ax^2+bx+c, the y-coordinate of the vertex is the minimum value of the function when a>0.
Let's identify the values of a and b in the given quadratic function.
f(x)=x^2-5x+4
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f(x)= 1x^2 - 5x+4We can see above that a= 1 and b= -5. We will now use these values to find the desired information.
Since a= 1 is greater than 0, the parabola will open upwards. This means it will have a minimum value, which is given by f ( - b2a ). Before we find the value of the function at this point, we need to substitute a= 1 and b= -5 in - b2a.
