McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
1. Graphing Quadratic Functions
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Exercise 16 Page 99

Practice makes perfect
a

For the quadratic function h(x)=ax^2+bx+c, the y-coordinate of the vertex is the maximum value of the function when a<0.

Let's identify the values of a, b, and c in the given quadratic function. y=- 2x^2+8x-6 ⇕ y= - 2x^2+ 8x+( - 6) We can see above that a= - 2, b= 8, and c= - 6. We will now use these values to find the desired information. Since a= - 2 is less than 0, the parabola will open downwards. This means it will have a maximum value.

b

The maximum value is given by substituting - b2a for x. Before we find the value of the function at this point, we need to substitute a= - 2 and b= 8 in - b2a.

- b/2a
â–¼
Substitute values and evaluate
- 8/2( - 2)
- 8/- 4
8/4
2

Now we have to substitute 2 for x in the given equation.

y=- 2x^2 +8x -6
y = - 2( 2)^2 +8( 2) -6
â–¼
Simplify right-hand side
y = - 2(4) +8(2) -6
y = - 8 +8(2) -6
y = - 8 +16 -6
y = 2

This tells us that the maximum value of the function is 2.

c

Unless there are any specified restrictions on the x-values, the domain of a quadratic function is all real numbers. Therefore, the domain of this function is all real numbers. Furthermore, since a= - 2 is less than 0, the range is all values less than or equal to the maximum value, 2.

Domain:& {All real numbers} Range:& {y | y ≤ 2}