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Start by identifying a, b, and c. The maximum value of the given quadratic function is f ( - b2a ).
Start by identifying a, b, and c. The maximum value of the given quadratic function is f ( - b2a ).
Start by identifying a, b, and c. The maximum value of the given quadratic function is f ( - b2a ).
Maximum
6
Domain: {All real numbers}
Range: {y | y ≤ 6}
For the quadratic function h(x)=ax^2+bx+c, the y-coordinate of the vertex is the maximum value of the function when a<0.
Let's identify the values of a, b, and c in the given quadratic function. y=- 3x^2+6x+3 ⇕ y= - 3x^2+ 6x+ 3 We can see above that a= - 3, b= 6, and c= 3. We will now use these values to find the desired information. Since a= - 3 is less than 0, the parabola will open downwards. This means it will have a maximum value.
The maximum value is given by substituting - b2a for x. Before we find the value of the function at this point, we need to substitute a= - 3 and b= 6 in - b2a.
a= - 3, b= 6
a(- b)=- a * b
- a/- b= a/b
a/a=1
Now we have to substitute 1 for x in the given equation.
x= 1
Calculate power
Identity Property of Multiplication
Add and subtract terms
This tells us that the maximum value of the function is 6.