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Start by identifying a, b, and c. The maximum value of the given quadratic function is f ( - b2a ).
Start by identifying a, b, and c. The maximum value of the given quadratic function is f ( - b2a ).
Start by identifying a, b, and c. The maximum value of the given quadratic function is f ( - b2a ).
Maximum
3
Domain: {All real numbers}
Range: {y | y ≤ 3}
For the quadratic function h(x)=ax^2+bx+c, the y-coordinate of the vertex is the maximum value of the function when a<0.
Let's identify the values of a, b, and c in the given quadratic function. y=- x^2-2x+2 ⇕ y= - 1x^2+( - 2)x+ 2 We can see above that a= - 1, b= - 2, and c= 2. We will now use these values to find the desired information. Since a= - 1 is less than 0, the parabola will open downwards. This means it will have a maximum value.
The maximum value is given by substituting - b2a for x. Before we find the value of the function at this point, we need to substitute a= - 1 and b= - 2 in - b2a.
a= - 1, b= - 2
Multiplication Property of -1
a/a=1
Now we have to substitute - 1 for x in the given equation.
x= - 1
Calculate power
Distribute -1
- a(- b)=a* b
Add and subtract terms
This tells us that the maximum value of the function is 3.